Taking Three as the subject to reason about —
A convenient number to state —
We add Seven, and Ten, and then multiply out
By One Thousand diminished by Eight.
The result we proceed to divide, as you see,
By Nine Hundred and Ninety Two:
Then subtract Seventeen, and the answer must be
Exactly and perfectly true.
Not all of Thomas Cranmer’s 42 Articles made it into the Elizabethian 39 Articles of the Anglicans.
19840 10 = 231504 6 .
231504 10 can be devided by 42 10 or by 39 10 without remainder.
But did Lewis Carroll know that? 😉
(x+7+10)×(1000-8)/992-17 = x,
for x=3:
| 3 | 3 |
| + 7 | 10 |
| + 10 | 20 |
| × (1000-8) | 19840 |
| / 992 | 20 |
| – 17 | 3 |
| 100110110000000 2 | 1111100000 2 |
| 1000012211 3 | 1100202 3 |
| 10312000 4 | 33200 4 |
| 1113330 5 | 12432 5 |
| 231504 6 | 4332 6 |
| 111562 7 | 2615 7 |
| 46600 8 | 1740 8 |
| 30184 9 | 1322 9 |
| 19840 10 | 992 10 |
| 139A7 11 | 822 11 |
| B594 12 | 6A8 12 |
| 9052 13 | 5B4 13 |
| 7332 14 | 50C 14 |
| 5D2A 15 | 462 15 |
| 4D80 16 | 3E0 16 |
| 40B1 17 | 376 17 |
| 3744 18 | 312 18 |
| 2GI4 19 | 2E4 19 |
| 29C0 20 | 29C 20 |
| 22KG 21 | 255 21 |
| 1ILI 22 | 212 22 |
| 1EBE 23 | 1K3 23 |
| 1AAG 24 | 1H8 24 |
| 16IF 25 | 1EH 25 |
| 1392 26 | 1C4 26 |
| 105M 27 | 19K 27 |
| P8G 28 | 17C 28 |
| NH4 29 | 156 29 |
| M1A 30 | 132 30 |
| KK0 31 | 110 31 |
| JC0 32 | V0 32 |
| I77 33 | U2 33 |
| H5I 34 | T6 34 |
| G6U 35 | SC 35 |
| FB4 36 | RK 36 |
2024-02-14